I'm trying to figure out a way to determine my odds of winning at the flop vs. any random cards the other player could have in 2 player hold'em. I want to make it simple so given that a flop looks like this: Jack, Six, Three. Taking only into consideration the fact that pairs are the only good thing you can get (eliminating 2 pairs 3 of a kind and better) what is the % chance your opponent has the better hand or equal to your hand.
Jack, Six, and Three as the flop are only examples. What I'm really trying to get at is if you have the highest pair on the flop what are your chances your opponent could have equal to or better than your current hand. Same with middle pair on flop and low pair on flop. Then with Ace card high, King card high etc... If it makes it any easier it would even help to have the probabilities without pocket pairs counting if it makes things any easier.
onemore Poker Expert
Joined: Sep 16, 2004 Posts: 290 Location: U.S.A
Posted: Wed Sep 14, 2011 4:52 am Post subject:
I think there are only about 140-150 combinations of starting hands you can get. So there must be a list of all hands and probability of winning against 1 opponent pre flop.
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